Recent content by robindude

Sure. And if you can figure out how to get MS Paint to draw a complete circle around the point 0,0 which is in the upper left hand corner of the screen, I will be very impressed. I'll also use it! ^_^

Tried this... and I think I'm doing something wrong. -_- Circle of origin 150,150, radius also 150. My starting point is at 100, 290 (this is inaccurate, I know, but it's MS Paint drawing a circle, so that's about as close as it'll get). Arc length is 103, so: \theta = 0.68666 cos\theta =...

Well then... er... it should be simple enough. By that, the y coordinate doesn't matter at all. All that matters is the x. And, actually, basically you gave the answer right there, no hinting. When starting from any point x1,y1 (assuming center is at the origin for simplicity) then any point...

Suppose there was a perfect circle in nature. We can measure this to some amount, suppose 14 decimal places (or a thousand, or a googol, whatever you like, I'll use 14 for sake of argument). We check a possible perfect circle that really IS perfect, to infinite decimal places. We confirm...

I have a circle and I need to find a particular point along it. The circle has a known radius (r), center (a, b), and I know a coordinate point upon it (x1, y1), as well as an arc-length (d). From that point x1, y1, how do I find out the point x2,y2 which is arc-length d away from the point...