Thanks so much for the help :smile:! I managed to solve both length and cross-sectional area by rearranging the volume equation in terms of radius, and plugging it back into the equation for resistance to solve for length.
Homework Statement
You must complete the circuit of (Figure 1) in such a way that it draws a current of 0.450 A from the battery. The battery maintains a potential difference of 10.0 V with no load, but has an internal resistance of Rbatt = 15.0 Ω . The only material you have is 20.0 mm^3 of...