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Is There an Inequality Between L1 and L2 Norms?
Yea that works for the first part. Thanks for the reply. Any idea on the second part (square root of n)? I am thinking it may have to do with the projection vector (such as (1,1,1,1,1,1)) in a scalar product or something like.- roho
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- Forum: Calculus and Beyond Homework Help
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Is There an Inequality Between L1 and L2 Norms?
Homework Statement \|x\|_2\le\|x\|_1\le\sqrt{n}\|x\|_2 where |x|1 is the l1 norm and |x|2 is the l2 normHomework Equations See aboveThe Attempt at a Solution I have \|\mathbf{x}\|_1 := \sum_{i=1}^{n} |x_i| and \|x\|_2 = \left(\sum_{i\in\mathbb N}|x_i|^2\right)^{\frac12} I have tried to...- roho
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- Inequality L2 Norm
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- Forum: Calculus and Beyond Homework Help