this is not my homework..It was my homework...but i got it wrong, unfortunately my teacher did not write the correct answer....as my exam is approching...i am preparing for it. I am doing this course through ilc, ilc tutors are not available right now because of the break, thats why i wanted to...
so for b....q/m=ratio of pi-, do i sud in 1.6x10^-19 for q??...so 1.6x10^-19/8.6x10^8C/kg which gives me m=1.86x10^-28kg......doesn;t seem right to me:(.....HELP!!!!!
The charge to-mass ratio of the pi^- particle was determined in the example above.The charge-to mass ratio of the pi^- particle was determined. The charge-to-mas ratio of the electron is 1.76x10^11C/kg. a) predict which particle has a greater mass-the electron, or the particle. b) use the value...
well...this is it.....this is what the exact question is in the book. What i was thinking was q/m is the ratio which is 1.76x10^C/kg, i can use this to find m by pluging into q/m=the ratio, therefore q/ratio = m......but i m confused...is this m what the part b wants???
light wavelengths of 520nm and 630nm passes through a diffraction grating that contains 6000lines/cm. a) sketch a diagram of the image produced from m=0 to m=2. label the order of each fringe.b) calculate the angles for the first and second-order maxima that would appear on the screen. c) What...
Elementary particle(ANYONE PLZ HELP ME WITH THIS Q)
The charge-to mass ratio of the pi^- particle was determined. The charge-to-mas ratio of the electron is 1.76x10^11C/kg. a) predict which particle has a greater mass-the electron, or the particle. b) use the value of the elmentary charge to...
but we see all the rainbow colors in soap bubble because thickness of the bubble varies.....the bottom of the bubble is thicker......therefore we see red at the bottom/??
if the thickness of the soap bubble is much smaller than the wavelength of light, the result is destructive interference (dark color). the thickness required to produce constructive interference for red is larger than that required for blue. ....