Recent content by romakarol

Wait I found a simpler formula based on what you said: I can get v since the wavelength and frequency is given (wavelength=v/frequency). So if I re-arrange it to get L on its own, then L=[(m)(V^2)]/F, correct?

Edit: see new post

I'm not sure, someone asked the same question as me on some website and that formula along with "solve for L" was the one-sentence reply. I used it because it seems to involve all the values listed in the question and can be used to find L. Is it incorrect?

Going through my physics assignment tonight, so that's 10 questions I'll be posting. Since I'm thoroughly hopeless at this subject most of my attempts will be based on my elite google-fu or trawling through lecture notes, bear with me and thanks! 1. Homework Statement frequency (f)=160hz...

Right thanks for all the help, only took till 2:30AM to get the right answer :D. Totally worth it.

Thanks I think I have it: But why are you using just 1.5 as the old capacitance, isn't it 1.5x10^-6 as given in the question. Is the constant the 1.5 is being multiplied by being ignored for some reason? Taking it as 1.5 however: Cnew=[(12*1.5)/5] Cnew=3.6 k=3.6 : 1.5 k=1 : 2.4

Can anyone help me finish this off? I want my sleep.

So you mentioned in the other post that there are two formulas, and q is the same in both. What I didnt realize originally is that the 5V potential difference in the question is simply voltage (at least i think it is) so as I gather there are 2 equations: q=CV q=(12)(1.5X10^-6) q=1.8X10^-5C and...

Cheers that's something I may be able to work with I'll get cracking.

How can the attached formula be used without knowing either k (dialectric constant) or A (area of the plate)? Also in an example the 3o is 8.85X10^-12, is this a constant?

Homework Statement A parallel plate capacitor has a capacitance of 1.5µF with air between the plates. The capacitor is connected a 12V battery and charged. The battery is then removed. When a dielectric is placed between the plates, a potential difference of 5.0V is measured across the plates...

Homework Statement Two spherical objects are separated by a distance of 2.5 x 10-3 m. The objects are initially electrically neutral and are very small compared to the distance between them. Each object acquires the same negative charge due to the addition of electrons. As a result each object...

Homework Statement Two spherical objects are separated by a distance of 2.5 x 10-3 m. The objects are initially electrically neutral and are very small compared to the distance between them. Each object acquires the same negative charge due to the addition of electrons. As a result each object...

Im Carol, I have to survive 1 more semester of experimental physics in college before I get to drop it in second year and forget about it like a horrible horrible dream. I'm sucky at physics (didnt do it in high school) so I need as good a continuous assesment mark as I can get, so I'll be...