Recent content by roovid
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Calculating Power from Mass, Speed and Height - 250W
oh lol thnx for the input much appreciated my prob was i wasnt noticing that speed was constant, so the would have no change in the kinetic value- roovid
- Post #10
- Forum: Introductory Physics Homework Help
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Calculating Power from Mass, Speed and Height - 250W
w parallel to plane 85(10)(1/20) =42.5 p = (42.5 + 20)4 = 250W- roovid
- Post #6
- Forum: Introductory Physics Homework Help
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Calculating Power from Mass, Speed and Height - 250W
THANK U i think i got it out used the component of weight parallel the to the displacement axis for the F grav and it worked out. thnx again- roovid
- Post #5
- Forum: Introductory Physics Homework Help
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Calculating Power from Mass, Speed and Height - 250W
how do i find del E now? i do not understand how to proceed from what u said resistive force will be -ve please help- roovid
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Power from Mass, Speed and Height - 250W
work, energy, power helpp question: A man of mass 70kg rides a bicycle of mass 15kg at a steady speed of 4ms-1 up a road which rises 1m for every 20m of its length. what power is the cyclistdeveloping if there is a constant resistance to motion of 20N? Ans: 250W My sol'n so far...- roovid
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- Energy Power Work
- Replies: 10
- Forum: Introductory Physics Homework Help
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Determine the acceleration of a rocket.
lol i kno but some of the question i am doing are makin me assume some weird stuff for basic calculation purposes sorry.my error thnx fr the correction again- roovid
- Post #33
- Forum: Introductory Physics Homework Help
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Determine the acceleration of a rocket.
oh my bad then i thought for calculation purposes only they wanted u to assume tohe rocket fell aft fuel ran out thanks for clearing up the free fall term for me- roovid
- Post #31
- Forum: Introductory Physics Homework Help
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Determine the acceleration of a rocket.
srry incorrect wrking was put here- roovid
- Post #29
- Forum: Introductory Physics Homework Help
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Newton 2nd law, forces and vectors
part a using g as 10 f = ma (1000 + 600)(1.2) 1920NF component paralled to plane inclined (1600)(10) Sin∅ (1600)(10)(1/20) =800N driving force 1920+800+200+100 =3020N ...... part b 1920 - 800 1120N lol oops- roovid
- Post #2
- Forum: Introductory Physics Homework Help
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Newton 2nd law, forces and vectors
A car of mass 1000 kg tows a caravan of mass 600kg up a road which rises 1m vertically for every 20m its length. There are constant frictional forces of 200N and 100N to the motion of the car and caravan respectively. the combination has an acceleration of 1.2ms-2 with the engine exerting a...- roovid
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- 2nd law Forces Law Newton Newton 2nd law Vectors
- Replies: 2
- Forum: Introductory Physics Homework Help
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Rate of change of momentum. Newton 2nd law
ohh... thankkk uu 1.2x30 36 yayy- roovid
- Post #9
- Forum: Introductory Physics Homework Help
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Rate of change of momentum. Newton 2nd law
i don't understand what to do with the force and the area 30m^2 sorry can u explain some more- roovid
- Post #7
- Forum: Introductory Physics Homework Help
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Rate of change of momentum. Newton 2nd law
so will it be change of momentum -.96 - (+.24) = - 1.2 N ? now what?- roovid
- Post #5
- Forum: Introductory Physics Homework Help
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Determine the acceleration of a rocket.
what is did was incorrect sorry- roovid
- Post #27
- Forum: Introductory Physics Homework Help
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Rate of change of momentum. Newton 2nd law
this was what i did so far mass for 1 second: 600 / (5x60) = 20 stones s-1 initial momentum mv (20)(.004)(12) =.96 final momentum 20(.004)(3) =.24 rate of change of momentum (.96) - (.24) =.72 =F stuck- roovid
- Post #3
- Forum: Introductory Physics Homework Help