Newton 2nd law, forces and vectors

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A car with a mass of 1000 kg tows a 600 kg caravan up an incline with a vertical rise of 1m for every 20m. The system experiences frictional forces of 200N for the car and 100N for the caravan, with a total acceleration of 1.2 m/s². The driving force exerted by the engine is calculated to be 3020N. For the tension in the tow bar, the resultant forces on the caravan are analyzed, leading to a tension of 1120N. This discussion highlights the application of Newton's second law in determining forces and vectors in a towing scenario.
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A car of mass 1000 kg tows a caravan of mass 600kg up a road which rises 1m vertically for every 20m its length.
There are constant frictional forces of 200N and 100N to the motion of the car and caravan respectively.
the combination has an acceleration of 1.2ms-2 with the engine exerting a constant driving force.
Find a. the driving force
b. the tension in the tow bar

i have the sol'n for part a
no clue for part b
will post my progress below
 
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part a
using g as 10

f = ma
(1000 + 600)(1.2)
1920NF component paralled to plane inclined
(1600)(10) Sin∅
(1600)(10)(1/20)
=800N

driving force
1920+800+200+100
=3020N
......

part b
1920 - 800
1120N

lol
oops
 
Last edited:
The force of the tow bar pulls the caravan. Find the resultant of all forces exerted on the caravan. You know its acceleration.

ehild
 
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