Ok so I calculated the normal force to be -3155.6 N and then divided this number by 3440 kg(the combined mass) to find the acceleration which was -0.9173 m/s^2. I then used this value to find the speed of the cars after the collision (which was 3.83 m/s). I used this value in the momentum...
Ok so does this mean that friction works only on the parked object after the collision? How would this affect the final answer and how would I incorporate that into my calculations?
I believe it just means that the speed of the moving car was constant before the collision, he didn't make an attempt to slow down. I'm not sure how this is supposed to affect the solution.
Homework Statement
A drunken driver crashes his car into a parked car that has its brakes set. The two cars move off together (perfectly inelastic collision), with the locked wheels of the parked car leaving skid marks 8.0 m in length.
If the mass of the moving car is 2290kg and the mass of...