Recent content by RoseCrye

to find the apparent depth, real depth over the n of what? tried it with the n of the water, and it's telling me it's wrong.

got some insight into the other problem of mine?

GOT IT! Thanks, hage!

theta1 with which n, glass or water?

How do you set up snell's law for a critical angle?! i thought snell's law didn't work with critical angles...

Tried pitting it in Snell's, hage, but it didn't work... I came out with 38.22 degrees, and used 43 degrees as the incedent angle. how do i find the crit angle in the water? if i use the glass' n, i'd only get 43 degrees again. i think i need the index of refraction at the water/glass...

what are you mean? Put it in Snell's Law?

Only thing I can think of to do with this problem is to state it as a tangent... that would give you theta. Can you do refraction problems?

this didn't work. what i did: Pythag. theorem => hyp=2.78m D(apparant)=D(real)/n D(apparant)=2.78/1.33 D(apparant)=2.09 Difference = .69m This answer was deemed incorrect. Say that ang.B=rt ang. Ang.A=observer's eyes to S (the angle that the light meets the water/air boundary...

WAITAMINNIT... sorry, that didn't register... thnx.

By the way, i worked it out, the index of refraction for the glass is 1.466, if that helps anyone... i just need at setup for this, I'm not asking for a solution.

but if you go from the standpoint that the observer is @ the side of the pool, how do you find the apparent depth?

Also, there is a question as to how to find the critical angle of a "special glass" (the index of refraction of which I am not given... o.O) when submerged in water. Hereis the question: "The critical angle for a special glass in air is 43°. What is the critical angle if the glass is...

there's a light source, S, sitting 2.60 metres below the surface of a pool 1.00 metres away from one side. I'm supposed to find the angle at which the light left the water and the difference between the apparent and actual depths of the light source. i attempted using Snell's Law with n...

looking for a formula... ooops. sorry, didn't think about that. problem was, i wasn't even sure how to do it. didn't have a formula, and i couldn't find one. that was really what i was looking for... i'll try to be more specific next time.