Recent content by Roy Fokker

Thanks for the response I was looking into it today, ill need a 3rd order system to achieve the desired results... There is always a trade off though. Ill report back when I have some more information. I am hoping I can achieve this with a modification to the original circuit.

Hello I am developing a low noise preamp and would like to change the roll off of my design to sharply decrease the gain for very low frequencies "1-5Hz". The results of my current design are as follows. I would need something that looked more like this.. I understand the simple equations...

Homework Statement Electrical force on a small positive charge q when it is placed in an electric field is given by F(r) = qE(r). Electric field is tangent at every point on a line of force. An analytical expression to plot electric field lines is given by E x dl = 0 Derive the following...

Ok so I did some fixin. (20-VL)/5k = IL + CdVc/dt + Vc/ 2k since VC = VL (20-VL)/5k = IL + CdVL/dt + VL/ 2k in the end... IL= -d^2IL/dt (LC) - dIL/dt (L 700m) + 4m

I was just staring at the same thing... Totally not right. I am looking at it from a steady state point of view. I see that since this is all in parallel I could say VL=VC. The inductor current is confusing me since it has no resistance. All I can see to do is integrate? Integral VL/L and...

I suppose I have some freedom to solve the deq for what I want. I guess i can leave it in the form of Vs= d^2/dt(x) + d/dt(y) +c Ok so I am going over my equations and looking at the node equations as you suggested. KCL I1=I2+I3+I4 (20-VL)/5k = LdiL/dt + CdVc/dt + Vc/ 2k **Kinda confused...

Yes Vc(0-)=Vc(0+) and iL(0+)=iL(0-) But can't current can change instantaneously in a capacitor and voltage can instantaneously change in an inductor. I say this because the equations for Ic and Vl where the derivatives are time based so it would.. at T=0 be zero. Ic(0-)=0ma because the...

Thanks! I am pretty excited it has been a long time without saying anything =)

Homework Statement Find DEQ, circuit for time t>0. Homework Equations Ic= CdVc/dt Vl=LdiL/dt The Attempt at a Solution At T=inf L Short , C Open IL(inf)=4mA, VL(inf)=0, Ic(inf)=0, Vc(inf)=0 T=0- All at 0 T=0+ L=Open C=Short IL(0+)=0, VL(0+)=0, Ic(0+)=4mA, Vc(0+)=0 20v=L diL/dt + Vc +...

Hi all! New here, well I have been lurking for some time now and I just finally decided to join up! In my junior year for EE. Looking forward to discussing issues here! =)