Recent content by Roynish

Okay. Will do. Thanks!

Okay thank you so much. Edit: I have to put this on a graph cost per km (data is given) vs power loss per Km. Do I still leave it as power loss per km of paralleled cable or for the sake of comparison change it?

Sorry I forget to square it. So the answer would actually be 2721600 Watts. This is per 2km so I divide it by two; 1360800 W/km. Yes that's correct. I'm wrong. Wow thanks. So can I use the current divider rule: R1 current: Itotal * R2/(R1+R2)?? So again: Merlin in parallel to pelican Current...

Okay, so the maximum current is different but the current flowing through each wire is the same. Gotcha. Okay say if I instead put Merlin in parallel with say pelican maybe I would not exceed the maximum current if current is split. How would I work out the current flowing through Merlin and in...

oh? I thought that if I put it in series with penguin there will be a net maximum current of 140 + 357(penguin's max currrent) = 497 A So if current is the same in each point in the series circuit...the overall max current should be the sum of the two wires' max currents...I assume... I feel...

Oh! I thought current is the same in parallel rather than series, sorry my mistake. Not necessarily I think. It can be in series. So: Say I did 1x swan, 1x penguin in series. Total Resistance: 17+4 = 21 ohms Current: 360 A Power loss: I²R 360 x 21 = 7560 Watts Is this correct? I did not surpass...

Hey everyone, This is quite a simple question, I think I'm just getting confused. 1. Homework Statement Given Data: Merlin: Resistance: 2 Ω / km, Maximum Current: 519 Pelican: Resistance: 1.5Ω/km, Maximum Current: 646 Penguin: Resistance: 4 Ω/km, Maximum Current: 357 Sparrow: Resistance...