Recent content by Rubber Band
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What is the Power Delivered by the Person Pulling the Rope?
[FONT="Courier New"][SIZE="5"]P=Fv=ma(vavg)SOLVE FOR [SIZE="4"][FONT="Courier New"]a: h=\frac{1}{2}at2 PLUG IN a and SOLVE FOR [SIZE="4"][FONT="Courier New"]vavg (which is v/2): v2=2ah- Rubber Band
- Post #5
- Forum: Introductory Physics Homework Help
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Inelastic collision to angular motion
http://img74.imageshack.us/img74/7216/physec7.png m1v1+m2v2 = (m1+m2)v IMPACT: Total Energy = 1/2mv^2 POINT P: 1/2mv^2+mgh = Total Energy at Impact- Rubber Band
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- Angular Angular motion Collision Inelastic Inelastic collision Motion
- Replies: 1
- Forum: Introductory Physics Homework Help
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Find the acceleration of a race car traveling up a curve
sqrt(1.09^2 + 0.000152^2) = 1.09 m/s^2 That's the same acceleration I got before. Is it correct?- Rubber Band
- Post #3
- Forum: Introductory Physics Homework Help
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Find the acceleration of a race car traveling up a curve
Homework Statement A 500 kg race car starts at rest on a curve with a radius of 50 m. If it goes 20 degrees in 4 seconds with a constant angular acceleration, what is its total acceleration at the end of this time? m=500kg r = 50 m angle = pi/9 radians time = 4...- Rubber Band
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- Acceleration Car Curve Race
- Replies: 8
- Forum: Introductory Physics Homework Help