Not sure where the 2ah is coming from in the middle step.
f(a+h)=-5(a+h)^2+2(a+h)-1 = -5(a^2 + 2ah +h^2) +2a +2h -1 = -5a^2 - 10ah -5h^2 +2a +2h -1
Please enlighten me
Should I be more impressed by the use of the word proviso? =)
btw you guys and this textbook is the closest thing to a teacher I have right now. Prepare for an onslaught and flurry
of annoying questions in the future.
$$y = cx + dx$$ solve for x textbook solution:$$x = \frac{y}{c+d}$$my steps:
$$\frac{y}{c + d}=\frac{cx + dx}{c + d}$$ here I divide to isolate x
$$\frac{y}{c + d}= x + x$$ simplifed
$$\frac{y}{c + d}=2x$$ adding the two x'sWhat am I missing here?