- #1

Rujaxso

- 11

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\(\displaystyle y = cx + dx\) solve for x textbook solution:\(\displaystyle x = \frac{y}{c+d}\)my steps:

\(\displaystyle \frac{y}{c + d}=\frac{cx + dx}{c + d}\) here I divide to isolate x

\(\displaystyle \frac{y}{c + d}= x + x\) simplifed

\(\displaystyle \frac{y}{c + d}=2x\) adding the two x'sWhat am I missing here?

\(\displaystyle \frac{y}{c + d}=\frac{cx + dx}{c + d}\) here I divide to isolate x

\(\displaystyle \frac{y}{c + d}= x + x\) simplifed

\(\displaystyle \frac{y}{c + d}=2x\) adding the two x'sWhat am I missing here?

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