You did the problem absolutely right, the 2.07 m/s was just thrown in there to trick you. Because it is at a constant speed, Newtons Second Law says the forces must be equal. The 2.07 was an arbitrary value that the skier is brought to before the incline, it could have been 1000 with the same...
Well, if you draw the free body diagram for figure 2, you simply have for each part, the one sitting on the table is:
Tension = m1 * a
The one hanging is:
mg - Tension = m2 * a
Plug in for the tension:
mg - m1 a = m2 * a
mg = (m1+m2) a
a = m/(m1+m2) * g
So you would need to...
Use Newton's Second Law.
F = m*a
Force of helicopter - mass of astronaut * g = mass of astro * 7.23
Therefore the Force the helicopter must exert is 7.23 m + mg
Work = Force x Distance, so its just (7.23 m + mg) (16.9) Joules. Good luck!
Try this out.
When the swing starts, there is only potential energy.
gh(m1+m2)
At the bottom, there is only kinetic
1/2(m1+m2)v^2. Therefore, equate these 2 quantities and solve for v. Now, Jane (m2) releases off. So the energy on the bottom becomes:
1/2(m1+m2)v^2 - 1/2(m2)v^2...
Homework Statement
"Consider a bead of mass m that is free to move around a horizontal, circular ring of wire (the wire passes through a hole in the bead). You may neglect gravity in this problem (assume the experiment is being done in space, far away from anything else). The radius of the...