Recent content by Rusho

well if it equals -10, then I think that would make the numerator zero. But I think I need to look at the denominator. So it cannot be zero

0, infinity

I'm confused on this domain question 10/ln x I really don't know where to start. Do I graph it and then go from there? :confused:

Without the equals 6 ^5x+3 =36 6 ^5x+3 = 6^2 5x+3 =2 5x = -3+2 5x = -1 5x/5 = -1/5 x= - 1/5 OH I see now I get "2" and 6^2 =36 :)

I got an answer, but I cannot get it to check correctly: =6 ^5x+3 =36 =6 ^5x+3 = 6^2 =5x+3 =2 =5x = -3+2 =5x = -1 x= 1/5 But I put 1/5 into the equation and it does not work out correctly.

Undefined!

Here is the problem again x^2-6x+9 / x^2 I think the answer is "all real numbers", but I don't know. I'm not used to seeing only x^2. Most of the ones I have done are x^2 - 4 or something like that.

A phone company offers a deal by which a long distance phone call costs .99 cents for the first 20 minutes and .07 per minute thereafter. Write a piecewise-defined function for the cost C of making a phone call that lasts x minutes. So I did this: f(x) { .99(6) 0<= x...

Ok, so I just do this: =2x^2 + 3x/x =x(2x + 3) / x =2x + 3

2x^2 + 3x I'm not really sure what to do with the "X" Form: f(x) - f(c)/ x-c -2(x)^2 +3(x) - (-2(0)^2 + 3 (0) / x-0 I get = -2x^2 + 3x + 0 / x - 0 = -2x^2 + 3x / x that doesn't seem right I'm taking a break

Great! Thanks for your help! I have another one, maybe I should start a new post

2(2)^3 + (2) - 2(1)^3 +1 / 2-1 =18-3 / 2-1 =15/1 =15

2(2)^3 + (2) -1 / 2-1 16+2-1 / 2-1 17/1 17 I'm sorry if I'm just not getting it

I think I got it 2(2)^3 + x - 2(1)^3 + x / 2-1 =16-2+x+x / 1 =14+2x =-2x + 14 x = -7

Ok, I am not sure what to do with 2x^3 + x . So I subtracted it from the f(b) - f(a). If I had 2x^3 by it self, I can see just putting 2(2)^3 - 2(1)^3 / 2-1 but the "+x" is confusing me