Recent content by Ryan Hwang
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Finding Coefficient of Kinetic Friction
Homework Statement See, I was collecting data for a lab, and now when I look it at, I'm being asked to find the kinetic friction force and the coefficient of friction. What I was given was: the mass of the block: .261 kg gravity: 9.81 m/s2 the acceleration: -7.3125 m/s2 And that's it. If it...- Ryan Hwang
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- Coefficient Force Friction Kinetic Kinetic friction
- Replies: 2
- Forum: Introductory Physics Homework Help
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Accelerating projectile force needed
There is no attempt at a solution.- Ryan Hwang
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- Forum: Introductory Physics Homework Help
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Kinematics: Find xf with v0, x0, t
Thanks for all the help! :)- Ryan Hwang
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- Forum: Introductory Physics Homework Help
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Kinematics: Find xf with v0, x0, t
If that were the case, then it wouldn't require all three equations would it? Just the second one, no?- Ryan Hwang
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- Forum: Introductory Physics Homework Help
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Kinematics: Find xf with v0, x0, t
Nothing else is stated other than what is provided. It's actually a problem from a summer assignment that is due the first day of the semester. There's no other information in the header, as it just provides a brief overview of instructions for the section, which is "Algebra", and it basically...- Ryan Hwang
- Post #3
- Forum: Introductory Physics Homework Help
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Kinematics: Find xf with v0, x0, t
Homework Statement Given v0=0 m/s, x0=0 m, and t=10 s, use all three kinematic equations together to find xf. Homework Equations vf=v0+at xf=x0+v0t+1/2at2 vf2=v02+2a(xf-x0) The Attempt at a Solution The more I look at this, the less sense it makes. First off, I tried to plug the values into the...- Ryan Hwang
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- Kinematics
- Replies: 6
- Forum: Introductory Physics Homework Help
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Ready to Ace AP Physics? Join Our Community of Physics Enthusiasts!
Currently a high school student that was a great interest in the fields of physics. Going to start taking an AP Physics course in the coming semester, and would love to learn more and review in the meantime!- Ryan Hwang
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- Replies: 1
- Forum: New Member Introductions