Recent content by s3a

Okay, so, in short, if there are at least two sources or at least one op amp, then polarity matters, right? What about if there is one voltage source and one current source? Polarity still matters then, right? Also, the circuit of this thread only has one source, right? I ask because that's...

Thanks for the answer, but unless I'm mistaken now, I think you misunderstood what I meant to say. Imagine ##V_+## wasn't something related to an op amp and is just the voltage at a node in a circuit with resistors and a voltage source. In that case, is what I said correct?

Okay, thanks. So, * for both the 40k ohm resistor and the voltage source, high potential is left of N1 and low potential is right of N1 because that's what is implied when current is assumed to move toward N1, right? * about the minus being tacked on to the 12 V, it was because the positive...

Ah! I think I get it, but just to make sure (I suppose, by reiterating what you said, but in my own words): * It's just about using the assumed direction of the current with the passive sign convention to know which part of the resistor is assumed to be the high potential difference and which...

All right, so V_out = _V_in * Z_2 / (Z_1 + Z_2) V_out = (-12 V)*(20k ohm) / (20k ohm + 40k ohm) V_out = (-12 V)*(1/3) V_out = -4 V V_+ = V_out = -4 V This does seem to be in agreement with what he found using nodal analysis, by the way. It seems to me, not just from the above, but just in...

Oh, so, it's just a matter of recognizing that the current, when flowing into node 1 (as defined by the instructor) (as opposed to away from it) and using the passive sign convention, the terminal of the resistor where the current goes into the resistor is positive and the voltage source's...

The last non-black frame of the video is attached as TheProblemAndItsSolution.png, as shown below. Here is the transcript of the video in its entirety.: "The topic of this problem is Operational Amplifier Circuits, and the problem is to find V out in the circuit shown below. It's a circuit...

I know how to solve each of those problems. For the set one, I look at the output of the S and try to match it with the input of T and then take the pair (input_of_S, output_of_T), and I do that for each pair. As for the formula one, I just plug in x = g(y). My confusion lies in trying to...

All right, thank you. :) (And, sorry for the delay!)

Actually, the sub-sequence examples I mentioned are not valid because of the third or fourth sentences (□[p → O q] or □[q → O p]), depending on whether it's p or q that's the last element of the sub-sequence, and not because it is generally the case that all moments in time need to be "occupied"...

Also, is my (latest, corrected) diagram correct? It seems correct to me (since it seems to graphically represent both structures 1 and 2), but I'm asking just in case. And, is it correct to say that each of the subsequences I mentioned are each not sufficient to show that the set of sentences...

So, there are an infinite number of sequences but only two structures (where if even an infinite amount of sequences can be expressed as part of one formula, it's one structure)? And, I see, thanks. :)

"The second formula in your diagram is not consistent with the problem statement, containing a rogue additional 'not' sign." Oops! For what it's worth, here is the corrected version.: "Not necessarily true. For instance if both t1 and t2 are always active then statement 1 fails. You need to...

Consider the following set of sentences that represent the requirements of a multi-threaded system for two threads t1 and t2: □¬[(t1 active) ∧ (t2 active)]. □[(t1 active) ⊕ (t2 active)]. □[(t1 active) → O(t2 active)]. □[(t2 active) → O(t1 active)]. (Pretend the O letters are the circles...

Thanks for your input, Babadag, but I still don't fully understand how to compute the connection of the two "sub-circuits". I also don't understand why multiplying the two transfer functions isn't good enough. Could you please elaborate on those? Having said that, I figured out how to do the...