Recent content by sadpwner

Then, N=W+Fc?

Track pushes sled upwards. Centripetal is towards the centre so that is upwards as well.

N=W-Fc =mg-mv^2/r =41*9.8-41*85.97/3.2 =-699.69N

Wow, I got it wrong somehow. Continuing from where I left off: 2*9.8*4.3+1.3^2=85.97 41*9.8-41*85.97/3.2=-699.69N The normal force is negative?

Homework Statement A boy slides on a sled on the curved track sketched (black line). (Treat the boy and sled as a particle.) His mass plus that of the sled is m = 41 kg. Friction and air resistance are negligible (I want a sled like that!). His initial speed is v0 = 1.3 m.s–1. The height h =...

I just used theta=S/r formula. Should be 180*1.57? 5.5m/s north initial. Then 5.5m/s west final. Using tan inverse it gives 45 degrees? However, that isn't the answer.

I think the acceleration direction should be constant as the angle should be the same throughout the circle. I am not required to find the speed. I just need the direction of the acceleration in degrees. I also just remembered that theta is measured in radians. In that case, the working should...

Homework Statement A cyclist is initially heading exactly due North. He then initiates a turn to the West, the turn being a quarter circle with radius 12-m. He travels at a constant speed of 5.5-m/s during the turn. What is the direction of this average acceleration, measured anti-clockwise...