Homework Statement
Consider a polarised sphere of radius R the polarization is given by
P vector = (ar^2 + b) r hat = ( ar+ b/r) r vector
Where a and b are constantHomework Equations
Find the dipole moment of the sphere
The Attempt at a Solution
I knew that P (polarized)= delta p / delta...
well yeah I get it
thank you thank you so much
really appreciate it and thank you for your patient ..
Really thank you
my problems are solved ..
thank you again
if the charge will reside inside each plates .. that's mean the E will be moving from the +ve charge plate to the -ve charge plate
so there is no specific place for the charge !
is it like this way ?
maybe the charges will be distribute in each plates
or maybe it will be going toward the +ve charge ..
when the dielectric material placed the E its causing Dielectric polarization Because of dielectric polarization, positive charges are displaced toward the field and negative charges shift...
a) the charge will be in the inside of each plates
so I'm goin to take the first relation which is Sigma = Q/S
am I right ?
e) the dielectric materials prevent tha charges to flow through the materials so the Q will stay the same and doesn't make any change on the E
right ?
I'v doubts bout tha 2nd Q ..
C = m-3
D = m2/s
Q= m-3/s
so L = m ..
is that right !
while D grows by 10,000
" assume the remaining is constant "
L = 100
is that tha better way to explain tha part B in Q 2 ?
well okay I'll try .. but please I need ur correction
the 1st one bout simply eq. for capacitor
..
so az I learned the first one its bout
( charge density ( sigma ) = charge (q) / area ( S ) ) and cus its bout one plate I think I've to dividin the equ. by 2 !
so it 'll be like
Sigma = q/2*S...
Hey all I'd like to help me..
thnx in advance
here z tha Q's :
1) Two plane parallel conducting plates each have area S and are separated by a distance b.
One carries a charge +Q ; the other carries a charge -Q. Neglect edge effects
a) What is the charge per unit area on each plate ? where...