Thanks, for the moment let us forget the tangential derivative. I only need to compute this integral by parts
∫dqG0(q,r:k)∂G(q,r′)∂n
choosing u=G0(q,r:k) and v=∂G(q,r′)\∂n
so du=∂G0(q,r:k)\∂q dv=?
where ∂G(q,r′)\∂n= n.\grad(G(q,r′))
so what is the...