Recent content by SaltMiner

Yeah, the following slides (that I've added at the end here) make it clear what they were asking for. I do get that. But this question was presented in the presentation just after describing refraction and just after describing Snell's Law so I'm having trouble reconciling the question itself...

I recently had some trouble understanding refraction but after I finally understood where I went wrong (thanks to the people on this forum) I went back to my old lecture notes because I thought that what I recently learned didn't fit right with something that had previously been presented in my...

Thank you very much! @haruspex and @jbriggs444. I understand it now.

Thanks for the replies but I'm still not understanding it. I've gone to the trouble of presenting the answer given as follows: Here is a picture I found on the net with some added stuff on my behalf to help visualize the problem. It lists all of the current knowns. In this first step to...

By using Snell's Law and knowing that nair =1 and nwater = 1.35 the angle of refraction was worked out to be 31.58 degrees. The next step in the answer was to use this in the following way: 90 - 31.58 = 58.42 degrees. This is the angle below the surface of the water where the ray from the...

This is a question on a past exam at university. The answer was provided (for revision purposes and exam preparation) but I never understood it and it continues to frustrate me because even if I can't come up with the right answer to a problem, I'll at least 'get' (understand) the proper answer...

Hi everyone. I finished a basic science degree at university a few years ago and I haven't done anything with it yet but I still really enjoy science and learning. I thought I did pretty good at uni but after looking into it more it seems pretty daunting how much stuff there is to learn in...