Recent content by sam.green

Thanks for the help, Dyad! \int_{-\infty}^{\infty}-j Sgn(f)e^{j2\pi ft}e^{-b|f|}df = \\ \int_{-\infty}^{0}je^{j2\pi ft}e^{bf}df - \int_{0}^{\infty}je^{j2\pi ft}e^{bf}df The e^{-b|f|} added convergence. I ended up with j[\frac{1}{j2\pi t+b}+\frac{1}{j2\pi t-b}] But as b...

Hi Dyad, Thanks for your response. Could you please give me more details? Even Mathematica hates the integral. By the way, I am only confident that the first part is correct. h(t) = \int_{-\infty}^{0} je^{j2\pi f t}df + \int_{0}^{\infty} -je^{j2\pi ft}df =...

That worked. Thanks!

Hello, I am working through Signals and Systems Demystified, but I am at an impasse. I would like to take the inverse Fourier transform of H(f)=\begin{cases} -j&\text{if } f > 0\\ j&\text{if } f<0\end{cases} So h(t) = \int_{-\infty}^{0} je^{j2\pi f t}df +...

The expansion is correct.

I am working through Signals and Systems Demystified on my own. I need to integrate: \int_{-\infty}^{\infty}{sin(2t)e^{-|t|}e^{-j2\pi ft}} dt I first went about dealing with the absolute value sign by using the following \int_{-\infty}^{\infty} e^{-|t|} dt = \int_{-\infty}^{0}...