Recent content by Sameer_1987

Hello nvn, I do have a boundary condition menu. But there is not an option for inserting a load set number to my knowledge. We can select any surface or point in the volume and apply a force to it.

Hello nvn, Thank you for your reply. By that, do you mean applying surface loads on all those sections/surfaces and if i am simulating for 1st section then un-suppress the load on the 1st section and suppress the loads on all other sections and so on for all other sections? Sameer

Hello all, I have a problem in ANSYS workbench. I have modeled a curved hollow cylinder and I have divided the top face(ring shaped) into various sections as shown in the attachment picture. I am applying surface loads on those sections/surfaces. Is there a way that I can make the load move...

Oh btw, to check the uniformity of those 100,000 random alpha values that I generated, I had generated its histogram and it was quite flat.

hmmm...since alpha is a random variable between 0-180 i generated 100,000 random values. But I get what you are saying. That's a good point! Do you know if there is a way to generate for eg- 100,000 equally spaced values between 0-180 in R language? is it, seq(0,180,(180/100,000)) ? Thanks!

Hi guys, I found a simpler way to get the pdf. I generated some 100,000 random values of Alpha between 0-180 and used them to calcuate 100,000 values of phi. Then I got a histogram with abt 100-120 bins. Then i calculated the x coordinates of the pdf by adding the bin width and the y coordinate...

Hi Mute, So, are you saying to find the CDF of 'Phi' I need to calculate the inverse of , Φ(α)=(−0.000001274370471∗α^4)+(0.000393888213304∗α^3)−(0.037767210716686∗α^2)+(1.66089231837634∗α)−5.83257204679921 ? Thanks.

I think I forgot to attach the histogram image file in the last message.

Hi Chiro, I calculated a histogram of phi in 'R' language using the runif function as, Alpha=runif(50000,0,180) Phi=(−0.000001274370471*Alpha^4)+(0.000393888213304*Alpha^3)−(0.037767210716686*Alpha^2)+(1.66089231837634*Alpha)−5.83257204679921 Hist(Phi, breaks=50) and got a...

Hi Stephen, By 'y' do you mean 'phi'? I have attached a jpeg file which shows what I have done. I am not sure how to use the 'Alpha' intervals that I have got. Also, I think I can solve the quartic equation using the 'depressing the quartic' method that I read somewhere recently. Thanks!

Thank you Gentlemen for your inputs! I will work on this and keep you updated. Thanks again.

Thank you Stephen! This should be really helpful.

Can you tell me how I can find out, what kind of distribution I have?..I mean with the given expression of phi in terms of Alpha(which is a random variable between 0-180), can I find out what kind of distribution will phi have? Thank you!

Right, I can have 10,000 values or more between 0-180...Thanks!

Hi Bacle, Oh yes, I meant PDF of Phi...sorry for that typing mistake..I am trying to find the PDF of Phi.