Ok so far i have velocity of balls before hitting the ground using d = 1/2at^2 + Vit
this works out as 2= 5t^2
therefor t = 0.28 seconds
And then using V = a.t i get V at 2.8 seconds (g = 10m/s^2) for this example
Then for velocity after collision i find the Ep (potential energy) = m.g.h = 200...
Homework Statement
4. The double-ball bounce
Consider 2 balls on top of another that are being dropped from a height h = 2 m,
see the Figure below. They will hit the ground and bounce back and we want to
compute the velocity of the upper ball after the bounce.
(a) (b)
We can model this...
so then i rearrange to get 12 tan 30 = t
so t = 6.93
and then times t by Vx = 83.16 and t by Vy = 13.86
then do pythag to find the total displacement?
which comes out at 84.3
that seems too high...
Well i set up a basic right angled triangle with the Hyp being the slope downwards at 30 degrees.
The horizontal would then be set at 12.
this gives me a vertical componant thats 6.93, so i presumed that would be the distance but i think thats wrong and there is a more complicated method of...
I am having difficulties with this question as no height for the crater is given please help! :)
Homework Statement
AN astronaut is speeding over a level stretch of the Moon's surface at 12m/s in her small lunar rover. She drives over the edge of a crater, whose surface slopes downwards at an...