Recent content by Satoy

never mind I found a website before I even got one view...thanks anyways

I am struggleing here. Can anyone explain this concept to me? I don't understand how to first find the forces the supports exort and even if I did I don't know I I could proceed. Does anyone know a website that has a non-symetrical triangle that I can re-learn the basics off of. Or if some one...

I'm looking for two answers on at the wheel and the other at the orgin.

I don't know if you are thinking about it right. There is only one force to begin with the 300 N at the top going horizontal in the positive x direction. At the orgin there is a stationary pivot point and a wheel at the other end on the x axis. The -400 N force I translated to the wheel from...

How do you change a moment about a point into a force is my main problem. I have a force of 300 N at the top of a L shaped bracket h=240 mm. So at the other end of the L at l= 180 mm the force would be -400 N right? Because at the orgin the moment would be 72000 N*mm. So what is the reaction at...

No...Pictures are made after light is exposed to film...Take one piece of light as follow it in your mind the distance from the film to the mirror...reflected...and back to the film...what is the distance?

Ok tension on M_1 has something to do with the pulley and T on m_2 should be greater but what is the equation? M_2 is the equation above but what is the other?

Look at his hint more closely...He says The image in a plane mirror is the same distance behind the mirror as in front...so think about it.

A block of mass 2.00 kg and a block of mass 6.00 kg are connected by a massless string over a pulley in the shape of a solid disk having a radius of .25 m and mass 10 kg. These blocks are allowed to move on a fixed block-wedge of angle 30 degrees. Friction = .360 for both blocks. Ok I don't...

Let me see if I am right the F to move Juliet needs to be applyed to the total system right?

Oh ok you just put me in the right state of mind, I got it now.

Ok I've got it now...thanks for all the help.

I've got most of the problem completed but I need a little help on the last little bit. Julet moves across the boat 2.7m to romeo to give him a kiss. Romeo and the boat weigh 157 kg and Julet weighs 55 kg. How far does the boat move. The boat is at rest before hand. The answer is .7m and I...

the units would be kg*m/s for (a) right? And for (b) J

The change in momentum would be 90 m/s right 50-(-40). And I am not quite sure I understand your equation because I don't have a delta t. Do I?