clearly you should first investigate alluminum because obviously its cheap and lightweight and strong enough for robots that are not designed to withstand destructive forces.
Not sure what you mean by solving trig eqns.
the solve command solves eqns for given arguments. type
help solve
in the command window for some details and syntax
you can also try
help tan
help tand
help sin
help sind
etc. let me know how it goes.
truth is, its a confidential document which is why only some of the story is shown. I went on the assumption that the information given would be enough for you to understand.
If you are going to use unit load of 1 you still have to use the units.
since you didnt, the units are wrong for...
Here's another question:
I was doing this problem via FEM by hand and came out with another spring coefficient. It's in the attachment, check it out tell me what you think.
the spring constant k is found in the very last equation and is the first term to the left of the equal sign that...
Cool! thanks.
not to make it seem like I don't believe you, because I do and that constant looks familiar. but I'm preparing a calculation document for a company. Do you happen to have the source of that info?
well if you work out the units to what i posted you will see that the k has units of N/m, aka stiffness (not deflection of units 'm')
That is the stiffness of the beam, or how much force it takes to deflect the beam 1 unit of length depending on what set of units are used.
Does anyone know the spring constant for a clamped/fixed beam with length L that is uniformly loaded? I know the spring constant for a clamped beam that is centrally load by a point load is
k= 192EI/L^3
I know for a uniformly distributed is different.