Recent content by schinb65

I am having a little trouble remembering the rules with derivatives. $\frac{a}{1-r}$ I know that it should be (derivative of the top*bottom - top*derivative bottom) / (bottom squared). $\frac{d}{dr}\frac{a}{1-r}$ I tried this got the answer wrong, and looked up how to do this and they showed...

Two independent events have probabilities 0.1 and 0.3. What is the probability that at least one of the events occurs? I have an answer of .37, when I looked up the solution it is the same value but it was solved another way. I was just wondering if my logic would work. Find $P(a \cup b) =...

A marketing survey indicates that 60% of the population owns an automobile, 30% owns a house, and 20% owns both an automobile and a house. Calculate the probability that a person chosen at random owns an automobile or a house, but not both. I am Told that the answer is .5, I did this...

I think I got it, I can say this correct? $Pr(A)= Pr(A\cap H) + Pr(a\cap H^c)$ Thus if I use algebra I can work it around to get $Pr(A)-Pr(A \cap H)=Pr((A\cap H^c)$

I am studying for an actuary exam. It has been years since I took a Stats/probability class. I am not really sure where I can find formulas that are the same. I have this $Pr(a\cap h^c)$, so i believe that I can say $Pr(a\cap 1-h)$ is that true? The solution has this: $Pr((a\cap h^c)$ =...

In modeling the number of claims filed by an individual under an automobile policy during a three-year period, an actuary makes the simplifying assumption that for all integers n ≥ 0, $p_n+1 = \frac{1}{5} p_n$ , where $p_n$ represents the probability that the policyholder files $n$ claims during...

Hello, I am wondering how to do this problem. I have a way that gave me the correct answer but I would not want to do this every time or for large numbers. What I did: So 2^5 equals 32 since the probability is 1/2 and I want 5 flips. Then I have 4 ways that the 2nd head will land on the...

Re: indestinguishable objects Thank you. The 1000 bring the values down to 20 objects gives me the correct answer. Thanks

Re: indestinguishable objects The calculator is a TI 84. I figured out the problem with the calculator. It computes the 3000! first then does the division. This number is too large but if you simplify the numbers it works. Thank you.

An investor has 20000 to invest among 4 possible investments. Each investment must be a unit of 1000. If the total 20,000 must be invested, how many different investment strategies are possible? What if not all money need to be invested? I should solve ${\binom{20000+4-1}{20000}}$? I think I...

Thirty items are arranged in a 6-by-5 array. Calculate the number of ways to form a set of three distinct items such that no two of the selected items are in the same row or same column. I am told the answer is 1200. I do not believe that I am able to use the standard combination formula...

Let a, b and c be three subsets of universe U with the following properties: n(A)= 63, n(B)=91, n(c)=44, The intersection of (A&B)= 25, The intersection of (A&C)=23, The intersection of (C&B)=21, n(A U B U C)= 139. Find the intersection of (A&B&C). I am told the answer is 10. I tried drawing...