Recent content by schu9600

So based on the graph the half life would be approximately 20 seconds. Umm for the rate of change of the concentration would you take the slope of the tangent line at a spot on the graph? Or is there a way to get the change of concentration for the whole thing not just an instantaneous point...

Well I would say that for a first order: v=kr [NOBr]1 and a second order would be: v=kr [NOBr]2 Not really sure how to do the d/dt part. Never fully learned/understood derivatives.

Here is my graph? Can you please help me out? I want to figure out how to do this.

The graph didnt attach trying again. Says invalid file when I try to upload. Not sure how to attach the file =/

Well the order of the reaction is the power by which the concentration of the substance is raised to in the rate law. I was thinking the NOBr would be a first order reaction because there is no coefficient in front of it in the equation so it would not be raised to any power (or it would be a...

Homework Statement Consider the following reaction NOBr (g) → NO (g) + ½ Br2 (g) The table below gives the time-dependent concentration of NOBr. Using this data, determine, if the reaction is first- or second-order, with respect to NOBr. Give the rate equation and determine the rate...

Homework Statement The dissolution of 5.25 g of a substance in 565 g of benzene at 298 K raises the boiling point by 0.625°C. Note that Kf = 5.12 K kg mol-1, and Kb = 2.53 K kg mol-1, and the density of benzene is 876.6 kg m-3. Calculate the freezing point depression, the ratio of the...

Thanks that cleared up that question. :biggrin:

Okay so I've figured out the energy to be 282.15 kj/mol For the rest of the parts I seem to get 0 for all of them. This doesn't seem right to me. Any advice? I've been doing N2/N1 = 3^-(282150J)/[(1.381x10^-23J/K)(2500K)] Using this I get an answer of 0 I get the same answer with a...

After thinking about it a bit more would the energy difference just be the energy of a photon of light with the wavelength of 422.7 nm? If someone could confirm this I'm pretty sure I could figure the rest out.

Homework Statement The first excited state of Ca is reached by absorption of 422.7-nm light. • Find the energy difference (kJ/mol) between ground and excited states. • The degeneracies are g*/g0 = 3 for Ca. Find N*/N0 at 2 500 K. • By what percentage will N*/N0 change with a 15-K rise in...