But, in usual cases, such as calculating forces given by an object to a wall, the time used is time taken in collision, not time taken for the object to move from a point to that wall and back to that point again. Why it doesn't apply here?
Refer to formula: delta p / delta t = F
delta t is...
The kinetic theory of gas state that p=(1/3)(N)(m)(u^2)/(V).
In one step of its derivative related to change of momentum and force given to the wall (Refer to Cubic Container and molecule movement in x,y,z axes in attachment), the equation is given by:
change in momentum / time = force...
Hi all, i have a question relating to the period of pendulum. I got this question:
A bob of mass 0.5 kg is suspended by a string from the ceiling inside a train moving on a straight level rail (to the right). If the train has an acceleration of 0.2g, what is the tension in the string when the...
Thanks for your responses.
But, how if the case is like this (attachment - rolling the ball).
Then surely, the point where the friction force is exerted do have velocity. It move downward and experience the gravitational acceleration.. I still don't get it..
How if the object is spinning on earth, where the gravitational acceleration (g) still exist? The ME I'm talking about consist of PE=mgh, where g still exist. If the object is on space, where g doesn't exist, then the law doesn't apply anymore.. It's a different case..
I found something interesting in the law of conservation of mechanical energy related with rotational kinetic energy. The law states that:
ME = KE(translational) + KE(rotational) + PE
*ME = Mechanical Energy
*KE = Kinetic Energy
*PE = Potential Energy
It was stated that the above law...