Using Vector in Determining Period of Pendulum Inside a Moving Train

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SUMMARY

The discussion centers on calculating the tension in a pendulum string inside a train accelerating at 0.2g. The pendulum bob, with a mass of 0.5 kg, experiences two forces: gravitational force and tension. The tension vector combines the vertical component that balances the weight of the bob and a horizontal component that results from the train's acceleration. The net force acting on the pendulum bob is not the tension itself but the resultant of the tension and gravitational forces.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of vector addition
  • Familiarity with concepts of tension and gravitational force
  • Ability to analyze forces in a non-inertial reference frame
NEXT STEPS
  • Study vector decomposition in physics
  • Learn about forces in non-inertial frames of reference
  • Explore the dynamics of pendulums under varying acceleration
  • Investigate the effects of acceleration on tension in strings
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of pendulums in accelerating systems.

science_world
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Hi all, i have a question relating to the period of pendulum. I got this question:
A bob of mass 0.5 kg is suspended by a string from the ceiling inside a train moving on a straight level rail (to the right). If the train has an acceleration of 0.2g, what is the tension in the string when the bob is at rest with respect to the train? (picture 1)

Someone explained to me that we must draw the tension as a vector joining the force by train to the pendulum and the pendulum's weight (picture 2). I don't understand. Isn't the pendulum supposed to be the resultant of those 2 forces (picture 3) and not the force by train who become the resultant (picture 2)?

Please do explain. Thanks a lot.
 

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science_world said:
Isn't the pendulum supposed to be the resultant of those 2 forces (picture 3) and not the force by train who become the resultant (picture 2)?
The net force is not the tension. The forces acting on the pendulum bob are gravity and tension. They add together to give s horizontal net force that you have labeled as F in your diagram. So you add a tension that is "up" and "to the right" to the weight that is "down". The "up" part of the tension exactly cancels the "down" weight and all that's left is the "to the right" part of the tension. There is no force exerted by the train.
 

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