Recent content by Scooter I

How would I find the initial speed, since I'm only given a diameter of 20.0m?

Homework Statement Homework Equations PE = mgh KE = \frac{1}{2}mv^{2} W = ΔKE W = Fd The Attempt at a Solution g = 9.80m/s^{2} hi = ? hf = 20.0m PEi + KEi = PEf + KEf mghi = mghf Would you then cancel the masses out? If you did, the initial height would be 20.0m...

Thanks. The answer was right!

Ah, the magnitude of the vector sum is the hypotenuse given by the formula Vb/d^{2} = Vb/w^{2} + Vw/d^{2}. Vb/d = √(4.0m/s)^{2} + (6.93m/s)^{2} Vb/d = 8.0 m/s Correct? PS: Thanks for all your help, I really really do appreciate it.

So Vb/d (where dock is d) = Vb/w + Vw/d Vb/d = 6.93m/s + 4.0m/s Vb/d = 10.93 m/s Correct?

I think I understand now. Would it be tan30 = (4.0m/s)/(Vb/w) Vb/w = 6.93 m/s? Also, how would you answer the second part?

How would you solve for it? Would it be sin30 = 4/V. V = 8?

Homework Statement A river is flowing 4.0 m/s to the east. A boater on the south shore plans to reach a dock on the north shore 30.0 Degrees downriver by heading directly across the river. What should be the boat's speed relative to the water? Also, what's the boat's speed relative to the...

Would B be: Bx = 32.0km By = 32.0km sin 75 = 30.9km And then the angle would be 17 degrees? But I don't know what direction.

Homework Statement Sudhir walks 0.40 km in a direction 60.0° west of north, then goes 0.50 km due west. What is his displacement? Homework Equations According to my textbook, the equations are: Ax = A cos θ Ay = A sin θ Bx = B cos θ By = B sin θ θ = tan-1 opposite side/adjacent side...

Can anyone else verify that I'm doing it correctly...? I really don't think so.

Homework Statement I set out on a compass heading of 15.0 degrees west of south for 23.4km. I turn 20.5 degrees east of south and travel another 32.0km. What is my displacement? Homework Equations I'm not sure if there are any. But these should help. Ax = A cos θ Ay = A...