If the radius of the big cylinder is r1 and the small cylinder r2, then I would think that the coefficient could be expressed as T1*r1/F where T1 is the torque on the big cylinder and F is the applied force. It would also be expressed as T2*r2/F. Does that sound right?
I work for a company that produced drill pipe. One of the engineers designed a machine that simulates the drill pipe wearing against the side of the hole. This particular machine uses two cylinders in contact rotating in opposite directions to measure the amount of wear to the surface of the...
I have two hollow cylinders of different sizes. The smaller cylinder is inside the larger cylinder but NOT concentrically. The OD of the smaller cylinder contacts the ID of the larger cylinder at the 6 o'clock position. Both cylinders rotate but in opposite directions. An actuator pushes the...