Recent content by scw287

I'm still not sure how to find the melting of the ice, do i need to use latent heat constant? ahhh so add the two values together and then multiply by the area*the density?

good after I find that I need add that to melting the ice. How does the area and the density come into play?

So I need to use the formula Q=mass*specific heat*change in temp for the first part right?

Specific heat for water=4186

is the latent fusion the same thing as the temperature for which ice needs to be in order to melt?

well the melting point is at 0. degrees celcius

1.if i raise the temp of the ice to the melting pt. it would need to be at its boiling pt 100 degrees celcius. heat rises 2. now must melt the ice at 0 degrees celcius I'm sorry I really don't know what I'm doing just learned this for the first time today along with four other physics chapter...

Homework Statement A woman finds the front windshield of her car covered with ice at -12.8°C. The ice has a thickness of 4.60 10-4 m, and the windshield has an area of 1.25 m2. The density of ice is 917 kg/m3. How much heat is required to melt the ice? Homework Equations Q=mL or change...

sometimes i just try to complicate problems...thanks for your help I appreciate it very much ;-)

o sorry, When you convert these to Fahrenheit degrees, it means 176.13 Fahrenheit degrees above freezing, where freezing is 32 F. so, Tf = (9/5)*Tc+32

Man I was making this problem much tougher than it was! thanks for your help!

first i would take the celcius and subtract 32 degrees since its above the farenheight freezing pt. and then convert to farenheight by multiplying by (9/5)...right...and in the other part i would add 32 degrees since its below the zero pt??

Oops So I need to subtract 32 degrees from each answer to take an account for the freezing pt.

Homework Statement On the moon the surface temperature ranges from 371 K during the day to 1.09 102 K at night. (a) What are these temperatures on the Celsius scale? (b) What are these temperatures on the Fahrenheit scale? Homework Equations T=Tc+273.15 T=Kelvin temperature Tc=Celcius...

that is much easier to understand!