Recent content by SeattleDrew

I read this hurriedly, but you may be thinking of the Bernoulli's for fluid dynamics (I don't know which Bernoulli wrote it, sorry). I'm not sure what you mean by "lift" equation. Maybe my response will call more people to help. I'll try and remember to read this agian later and give it some...

I agree with Strangelove. The CD will be changing rapidly as the size of the chute changes and it depends on how evenly the chute deploys. I found old textbooks about sailing with equations on how to calculate lift and drag, the drag equation looked similar to yours but ended up not working out...

The cats position will be c +/- the x component of bt and 0 + the y component of bt. and the mouse will be xm(t)=0 and ym(t)=bt. xc (t )= c+bx t yc (t )= by t I realize i can't just call them b sub x and y but I'm not sure how to show the relationship of the change, will it be something like...

Homework Statement A mouse starts at the origin and runs up the y-axis with a speed a. At the same time, a cat running with speed b, starts at the point (c,0) and pursues the mouse. i. What is the path of the cat? ii. Assume a<b and solve for y(x). How far does the mouse run before being...

This is for a research project that I'm designing myself. So I can tweak it however I need to. By that I mean, I haven't written it down as a project statement, but my aim is to find the equation of the camber line. I do know the importance of writing down a specific goal and I have overlooked...

I'm trying to do all of this without touching a sail (yet). What kind of computational program would I need to learn to be able to do this (I'm just a lowly, scum of the earth, undergrad)?

I'm picturing it as a sideways catenary, hanging in the direction of my lift and drag combined. Very ideal. Since a catenary assumes that the forces acting on it all face in the same direction, I think I might be at a fault. Even if I am, the shape should still be comprable. I plan on modeling...

I know a little bit about the design. I'm starting off with a uniformly dense sail that has no batons, tell tales, or any of the like. I started to try and derive the equation from scratch, step by step like you would get a catenary, but I ran into some pretty irreducible and messy equations...

I've been familiarizing myself with how to work with catenary equations for this project.

Considering the forces on a catenary all face the same direction and the forces on a sail rotate as they move about the sail should I scrap that idea? I thought I could use the combined force of drag and lift and equate that to the downward force of the catenary. It's quite possibly I have a...

Thanks for the tips. I know it's very complicated. I've been up and down those references. I am trying to over simplify it and say that the cross section was unaffected by the top and bottom and that the tension was applied at the beginning and end. And then start making adjustments from there...

When sailing into the wind the lift creates a force on the sail that makes a cross section of the sail look like the Nike swoosh. For a given wind speed, sail size, and angle of attack, the equation of the slope should always look the same. I believe another assumption that needs to be made is...