Recent content by SEEDS

Homework Statement a)Yellow light Lambda= 589nm falls on a double slit. The distance between two slits is d=0.5 mm the width of each slit is a=100 micrometer. A screen showing the interference pattern is located 4 m behind the slits. Homework Equations What is the distance between...

ok let's check it fn = n v/2L ---A fn+1 = (n+1) v/2L ----B fn = 466.2 Hz , fn+1 = 582.7 Hz Therefore A becomes 466.2 = n (343 / 2L ) 2.718L = n ------(i) and B becomes by fn+1 582.7L = 171.5 n + 171.5 ---(ii) putting n from i L = 1.471 meter and n is approx = 4...

f_n = n\frac{v}{2L} I am applying it like n = (fn * 2 L) / v but n1=2.718 L n2=3.397 L n3=4.076 Lstill confusion how to find L to proceed finally for the harmonics ?

The fundamental frequ. of an open pipe is f0 = v/(2*L1)

If I am using fn = n f1 so i am getting fractional figures 466.2 / 264 = n and i guess n should'nt be fractional . 582.7 / 264 = n 699.2 / 264 = n

could you confirm me about the fundamental fr in (C)

Ohh Sorry ! For C Please take a look at my first post.

Homework Statement One organ pipe open on both ends and one organ pipe open at one end and closed at the other are tuned on the same fundamental tone with frequency f = 264 Hz. a)How long is each pipe? b) Determine the first three harmonics of each pipe. c) There is an organ pipe open at both...

Ohh Sorry .. Now i got it , Tm4 = (T24 + T14)/2 Tm = 334.21 Kelvin How does the radiation balance of P2 change with the insertion of PM? What i m getting is radiation balance of P2 with P1 will change after the insertion but how can we define it ?

Thanks a lot for the help , sA(TM4 - T14) = sA (T24 - TM4) By canceling sA (TM4 - T14) = (T24 - TM4) Tm4 = (T24 - T14)/2 Tm4 = 6.9106 10^9 . How does the radiation balance of P2 change with the insertion of PM? Thanks again

Ok, Thanks a lot for the hint . I tried it please take a look at it ... According to Stefans LAW P=SAT^(4) P = Power radiated in W (J/s) s = Stefan's Constant 5.67 x 10-8 W m-2 K-4 A = Surface area of body (m²) T = Temperature of body (K)To Find out the temperature of Pm :- P...

***** SHEETS two ideally black of the area 1:5 mETER SQUARE are located opposite of each other in vacuum. The first SHEET P1 has the FIXED temperature T1 = 0o C, the second SHEET P2 has the fIXED temperature T2 = 100o C. Now an additional black panel PM of the same size is brought between the...