Recent content by Semoirethe

Thanks for your help. Me and my double and triple counting forces.

I found the acceleration to be = [Fcos(a) - (m1+m2+m3)gsin(a))/(m1+m2+m3)]. It's just all the weight "resting" on the middle block that is throwing me off when calculating the correct normal forces for friction. I think I'm having trouble of only looking at block 2 because it feels like...

Correct. I did the same problem first without the block being on the incline and it equals my answer here with theta = 0. However I do believe I should have taken into account the weight of block 3 pressing on block 2. Aka I messed up the stuff with sin theta >.< aka the whole problem. It's...

Correct, except block 2 isn't touching the ramp. It's skinnier so it's supposed to be held up by friction between it and the other two blocks.

Homework Statement Three blocks are on an incline of Theta(a), block 1 has mass of m1, block 2 has mass of m2, and block 3 has mass of m3. Block 2 is being held(theoretically) above the ground by friction between block 1 and block 3. What is the minimum magnitude of force positioned directly...