Recent content by shadowshed

Yes, you are correct. Hmm, what I call as "paired ones" are table1's rows X table2's rows. I believe you noticed that when you tried it before. So in the second query, we added a constraint WHERE TABLE1.COLUMN_A = TABLE2.COLUMN_B. The query executes the SELECT function first, and then it...

I mean TABLE1.COLUMN_A and TABLE2.COLUMN_B

This is about WHERE syntax, right? For example, when you have 2 tables and you run this query: SELECT * FROM TABLE1, TABLE2 you'll get the output rows, which each made of every row in TABLE1 paired with every row in TABLE2. So when you run another query like this: SELECT * FROM TABLE1, TABLE2...

I see. That's very observant of you! :)

I wonder how you'd know that the app use Phone permission. Do you mind explaining it to me? I'm aware of having control over the friend's phone situation. And for checking the same email account... I haven't really experienced any checking over it, since not every LINE account has registered...

There's a possibility that he might have gotten your number or perhaps asked a third person to share your contact information. There's also a feature where you can add people that appear in your timeline, but I guess it'll need your permission first to accept them. Nope. There's a number...

Ah, thanks. It helps that other people are actually experiencing it. It matches with the Interpersonal Complementary section well.. Thank you very much for telling me that! ============ On other random thoughts, do roaches have ears? I wonder if they can listen to sound. If they can, then in...

Have you ever felt that we sometimes act in opposite way to the other person we're with? For my example, I experience things like becoming braver around afraid people and step up to protect them, and get unreasonably childish when I'm around close friend who's more mature. Is there already...

You've got to make (log310x - log31) - 2 into one Log3. You don't really divide out the log, but comparing the values inside the logs. They have to be equals, since the logs would result the same.

Since 2log3x = 2 (Log3 + Log x) which means there will 2 Log 3, so there would be still one Log 3 remaining. Or you can just actually change the 2Log3x to Log(3x)^2, and then manipulate the left side of equation to be Log, and equals them.

By 2Log3, does it mean that it's a log with basis of 2 or 2*Log3?