Recent content by Shaq

I already handed in the assignment, but firstly I did a/sin a then c/sin c which got me a number, I divided that number by 30 which is how many m/s, then that got me that one side, then I divided that number by 60 to get me the answer in minutes.

I got the answer. I did sin law, which got me the answer in seconds which I then converted to minutes which got me 3.2. Thanks everyone for the help

Sort of but I'm not sure if it is right. I did 5 cos 30 which would get me 4.33, which I am assuming is the hyptoneuse? I'm not sure if this is right tho.

So how do I get the answer in minutes?

Oh so instead of just sin cosin and tan it would be either sin law or co-sign law??

I'm confused on how to use the trig functions. So is the hypotenuse a unknown variable and I would use a trig function to find it? Or is the 30m/s the hypotenuse? And once I have the hypotenuse, how would I convert to it to time or is it the time?

So, what possibly could be done with the trig relationships?

Yea, this is my last question of the booklet. So, throughout the booklet we were doing trig relationships such as cos, sign, tan, etc. So I would assume this would have something to do with that. So I'm assuming it doesn't have anything to do with the sides of a triangle, well it does, but not...

Here's my diagram I drew and the picture that came with the question. Also, to get from m/s to km I would assume you should multiply by 3.6?

Homework Statement A man drives a car starting 5.00 km due West from the line marking the Eastern time zone. He travels at 30 m/s along a straight road that runs in a direction E 30° N. How much time does it take the man to get to the Eastern time zone? (The man must travel along the road: no...