You found out the angular acceleration...NOT the angle present.
Try using proper required equations to find out the angle displaced
(Hint:- kinematic equations and equations for circular motions are pretty much the same
Draw a free body diagram.
Assuming the mass distribution is same, take the centre of mass at the centre i.e at 2.0 metre.
The plank is in translational and rotational equilbrium.
Thus, the sum of magnitude of the forces at the pivot is equal to the wieght of the plank.
And, the moments, or the...
The acceleration for both of them should be the same.
An acceleration is produced only when there is an external forces is applied.
after release, the only force on the balls is tat of gravity.
Thus the acceleration will be the same for both of them.
Alice's ball has more acceleration only...
force is the rate of change of momentum.
Thus, you have been given the change in momentum, the force excerted.
So,
t=Change in momentum/force
=2*1.5*25/50=75/50=1.5
Yup, your answer is correct
By kinetic energy on the pulley, if you mean rotational kinetic energy and that the pulley has a mass then we have to solve the problem in totally different way.
try considering the toque acting on the pulley due to the tension (if the two hanging masses are different) and then solving a problem...
if you want a physics book for the BASICS, just to build a base, try Idiot's Guide to Physics.
im not joking, its an actual book, and its a very good book. If you want to get more and more knowledge, you can then jump to resnick and halliday (that will be a big jump)
and one thing, DO NOT CARE...
Yes it does!
so probably, when you are observing a star thousands of lightyears away, you see how it looked thousands of years ago.
That start could be fizzled up, and dead, and you don't even know
Umm...i think you should take into consideration the kinetic energy due to rotation.
As we are talking about the whole system, NOT the frog, the kinetic energy will be given as
KE=1/2 Iw^2
where I is the moment of inertia, w is the angular velocity.
As per the law of conservation of angular...