Rotational motion: Find angular displacement when rotation speed is changing

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SUMMARY

The discussion focuses on calculating angular displacement when a wheel's rotation speed changes due to applied torque. The initial angular speed is 19.8 rad/s, increasing to 23.5 rad/s over a duration of 11.2 seconds. The correct approach involves using angular acceleration to determine angular displacement, rather than incorrectly calculating angular acceleration alone. The relevant kinematic equations for angular motion must be applied to find the angle through which the wheel turns during this time.

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mememe1245
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Homework Statement



A torque acts on a wheel rotating at 19.8 rad/s and increases its angular speed to 23.5 rad/s in 11.2 s. Find the angle through which the wheel turns during this time.

Homework Equations


omega = theta/time

The Attempt at a Solution


23.5 - 19.8/11.2 = .33rad/s/s --- this is wrong.
 
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Your thread title is non-descriptive of the thread content. I will change it this time.

Clearly the problem involves a change in rotation speed, so an angular acceleration is involved. You haven't presented any Relevant Equations involving acceleration.

Can you explain your attempt at solution? Use symbols rather than numbers.
 
mememe1245 said:

Homework Statement



A torque acts on a wheel rotating at 19.8 rad/s and increases its angular speed to 23.5 rad/s in 11.2 s. Find the angle through which the wheel turns during this time.

Homework Equations


omega = theta/time

The Attempt at a Solution


23.5 - 19.8/11.2 = .33rad/s/s --- this is wrong.

The problem clearly states, "Find the angle ..." Is 0.33 rad/s/s how you measure an angle?

Review your equations for angular motion. There should be one which gives you the angular displacement if you know: the time, the angular velocity, and the angular acceleration.
 
You found out the angular acceleration...NOT the angle present.

Try using proper required equations to find out the angle displaced

(Hint:- kinematic equations and equations for circular motions are pretty much the same
 
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