Since they r of diff masses , normal F will be diff. But since they r rolling friction is sufficient, ( By neglect friction, they mean ROLLING FR.)
SO, THEY WILL REACH SIMULTANEOUSLY.
PLz calculate its value by finding the equations.
I think its unsolvable as it involves very complex mechanism of friction.
Think hard & u will realize that its very very conceptual problem.
from 1st part
uMg cos 32.7= Mgsin 32.7
so
u=tan 32.7=0.642
now for 2nd part
a=-(o.642 cos 32.7+sin 32.7)g
=1.08g
s=v square/2a=(4.25)sq./1.08g
This was a pretty simple one
I am finding it very difficult to find frictional force & tension in this problem, since the system remains at rest. It requires something more than FBD & force eqations.
Q. Two blocks 10 kg(u=o.f) & 6kg(u=0.2) ( u:co-ef of friction) lie on a horizontal table, connected by string...