Okay sweet, I'm working this out now, I think you skimmed over the stuff that I worked out because I did a column swap so basically everywhere you have a c it should be a b.
But where I am right now, I have:
d=(-3/2)-5b
c=(8/3)b+124/3
b=(-3/10)-(1/5)d
So If I plug them into the...
Right, I understand that much, I just feel like I'm taking the wrong approach completely to starting this.
I'm completely screwed now since nothing I did was right
I emailed my prof about the question, asking him if the final cubic:
( (11/8+1019/16)x^3 + x^2 + (8/3+123/3)x+(-5-3/2)=0)
Was as incorrect as it looked.
He replied with this:
"You should get a row of zeros in your equation, giving you a homogeneous solution which is a cubic polynomial and a...
Homework Statement
The Attempt at a Solution
For Part A) I did the normal best fit straight line stuff, A^τAX=bA^τ etc, resulting in:
y= 31/26x -8/3
Now part B) is where I need a hand, I started with just cubing, squaring etc the terms given and doing row ops, which is where I'm at...
UGH, I'm pretty sure I messed up way back around the start.
http://www.wolframalpha.com/input/?i=[[1%2F143*67%2C1%2F143*33]%2C[1%2F143*44%2C-1%2F143*54]]
My eigenvalues are right, but 1 vectors wrong.
Oh damn, so it does.
So I'll have :
[cn dn] = 6*A^n[3 1] -3 *A^n[1 -4]
as the expression for cn & dn? or should they be seperate?
I'm guessing separate since it asks for a ratio in part b)
I just really don't understand what's going on.. I have
A[1,-4] = (-5/11)*[1 -4]
A[3 1] = (6/11) & [3 1]
But what am I trying to do? Get what in terms of what? :s Thanks for being so patient with me I feel like an idiot