Recent content by shnigglefratz

Thanks, I really appreciate all of the help :smile:. I just thought that the solution would involve more than one variable.

So the only factor that matters when comparing the two centripetal accelerations is the radius of their orbits. Therefore Mars has a larger centripetal acceleration because its radius is larger. Is that right?

so: m_{earth}a = \frac{G*m_{Earth}*m_{Sun}}{r^2} divide by m_{Earth}: a = \frac{G*m_{Sun}}{r_{Earth's Orbit}^2} Therefore for Mars the equation will be: a = \frac{G*m_{Sun}}{r_{Mars' Orbit}^2}

So with Newton's law of universal gravitation it's: F = \frac{G(m_{Earth})(m_{Sun})}{r^{2}}?

Homework Statement Is the centripetal acceleration of Mars in its orbit around the Sun larger or smaller than the centripetal acceleration of the Earth? Homework Equations I assume that the relevant equation is a=v^{2}/r since you are trying to compare the centripetal accelerations of Mars...