Recent content by shooba

If we place an infinite conducting sheet in free space, and fix its potential to \varphi_0, how do we solve solve for the potential on either side of the sheet? Since the potential blows up at infinity, it seems impossible to define boundary conditions.

Bump? Maybe this belongs in the classical physics section?

"Qausi-static" displacement current (Purcell) Hello all, On page 329, chapter 9 of Purcell's E&M book, he describes why the "displacement current" produces nearly zero magnetic field for slowly varying fields. By taking the curl of the displacement current Jd, he shows that...

Wow thanks, that's a lot clearer than the other derivations! Just one question; when we write dv/dx we are treating velocity as a function of x; does this somehow conflict with the fact that velocity is the time derivative of x and thus a function of t? Is "v" somehow a function of both? (this...

Hi, this question is about the mathematical justification for a physics topic so hopefully this is the right forum. All the proofs of the work-KE theorem I have found go something like this: W= int(F)dx from x1 to x2 = m(int(dv/dt))dx from x1 to x2 = m(int((dv/dt)v)dt from t1 to t2 =...

When finding the asymptote of a rational function, if the degree of the numerator is less than or equal to the denominator you can divide by the highest power in the denominator and then take the limit as x goes to +/- infinity. Apparently this trick does not work when the numerator is of...

In general terms, what I'm trying to "justify" is that if the limit, as x approaches a, of g(x) is b, and we define t=g(x), then the limit, as x approaches a, of f(g(x)) is equal to the the limit, as t approaches b, of f(t). In my case t=g(x)=1/x, f(t)=(sint)/t, a "=" infinity, and b=0.

I'm supposed to find the limit, as x approaches infinity, of xsin(1/x). I know that xsin(1/x)=[sin(1/x)]/(1/x), And that if I define t=(1/x), then, As x approaches infinity, t approaches 0 from the right. If I say that the original limit equals the limit, as t approaches 0 from the right...