Recent content by shqiptargirl

I know, I am sorry. I didn't see the last part of your reply because of the computer screen I am using.

You said this... "Yes, that would follow. You know the magnitude of q3, and the position of q2 in relation to it, so you can write an equation for that force as a function of q2's magnitude." I don't understand this part. I am lost on how to do this. And k btw is about 9 *10 ^9, atleast that...

The y direction force from q1 on q3 is 23.15 N. So The y direction force from q2 from q3 must be -23.15 N ? The problem is I don't know how to use this information to solve for the magnitude of q2. Also, what does this mean, "+ve x direction" ? I didn't understand your comment on how it...

Homework Statement Three charges are placed as shown in the figure below. The magnitude of q1 is 2.00 µC, but its sign is not known. The charge and sign of q2 is not known. We do know that q3 is +4.00 µC and the net force on q3 is entirely in the negative x-direction. a.) Deduce the signs of...

Thank you so much for all your help! I understand it now ;)

Okay I think I figured it out. If I expanded ##E = k \frac{-12q}{2d^2} ## I'd get ##E = k \frac{-12q}{2d*2d} ## which would simplify to -3? The thing I don't understand is how I can simplify this fraction when there is a variable D in the denominator. How can I take 2d out of 12 if I don't...

Okay, with this I got k *6q/2d^2+ k*-12q/2d^2. Can I know add them together to get k* -6q/2d^2 and then simplify to get -3q/d^2? Also, how do you format your fractions so nicely?

That's what I don't understand unfortunately. How do I add up the two fields? I know I have to make the denominators equal first. So I would multiply both the denominator and numerator of (9*10^9)(3)/d^2 by 2. From that point on I am confused. Am I suppose to distribute the 2 to both (9*10^9)...

That's what I have trouble understanding. I know the electric field at point E due to the +3 charge would be (9 * 10^9)(3)/d^2. And the electric field at point p due to the -12 charge would be (9 *10^9)(12)/(2d)^2. But I don't know where to go from there. How do I add them together if the...

Homework Statement What is the magnitude of the electric field at point p due to the four point charges shown? The distance d is between charge centers. Homework Equations Electric Field = kq/d^2 Coulomb's Law = k(q1q2)/d^2 The Attempt at a Solution I don't know how to go about solving this...