Recent content by shrutiphysics

Oh sorry i forgot...nCv=2,5R and nCp=3R. R=GAS CONSTANT

upto my knowledge when i use molar specific heat cp and cv then heat transferred first step=ncvΔT=2.5*T(temp changes from T to 2T) 2nd step=ncpΔT=3.5*T(temp changes from 2T TO 4T) And finally to find out molar heat capacity i added both the values and divided it by net temperature change i.e 3T...

Yes, the final temperature is three times the initial one, ΔT=3T is correct. The heat transferred is C n ΔT, but the temperature changes from 2T to 4T in the second step. (And nR is missing from your equation)[/QUOTe i am not getting the answer in any way.am i using wrong equation? and how can...

Homework Statement A diatomic ideal gas is heated at constant volume until its pressure is doubled. It is again heated at constant pressure until its volume is doubled. The molar heat capacity for the whole process is kR. Find the value of k. Homework Equations ans is k=19/6. p/t=constant...

thanks for leading me to answer.

is it like as hot air rise and hence the room with high temp has lower air molecules than the cooler one. if it is right then maybe i have got it.

thanks i finally got i

if i take pressure as constant and use charles law then volume is directly proportional to temperature.so higher temperature more air molecules, but the answer given is option b

Homework Statement A metal ball is connected to the ground with a wire via a switch. The switch is initially closed (i.e.the ball is connected to ground) while a charge +Q is brought close to the ball (but not touching). While the charge is near the ball, the switch is opened and then the...

Homework Statement Two identical rooms in a perfectly insulated house are connected by an open doorway. The temperature in the two rooms are maintained at different values. The room which contains more air molecules is (1) the one with the higher temperature (2) the one with the lower...

i am sorry but this is how the question was given in my book

volume at stp. is 22.4l. since we add 1mole gas it becomes 44.8l then should i use w=nrtlogv2/v1 (work done is isothermal process). but if i use this answer is not coming. i also thought that q=msdt and since temperature in second step is constant so q=0. is this correct?? the answer given is...

one gram molecule of monoatomic gas is taken at s.t.p. keeping its volume constant,its temperature is raised by 1k. one gram molecule of the gas is added isothermally to this.the mixture is now cooled by 1k at constant volume to return to s.t.p. if [c][/v] be gram molecular specific heat of gas...