Recent content by sidinsky
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Physics Do Physics (Research) Related jobs exists for Bachelor's holders?
Thank you, this is really helpful. The last advice proved to be very helpful and this really made things clear for me. I really appreciate everyone's input.- sidinsky
- Post #5
- Forum: STEM Career Guidance
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Physics Do Physics (Research) Related jobs exists for Bachelor's holders?
Thanks for your response. It was helpful. :)- sidinsky
- Post #3
- Forum: STEM Career Guidance
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Physics Do Physics (Research) Related jobs exists for Bachelor's holders?
I graduated with a Bachelor's in Physics a few years back and have been working in the education field (Private Institute) for a few years now. Although I am making serious efforts to at least go for my Master's now, I am also looking for positions related to my degree outside the education...- sidinsky
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- Jobs Physics Research
- Replies: 4
- Forum: STEM Career Guidance
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Please help with this matrix question Solve for Eigenvales, and Eigenvectors
well I managed to clean up the expression inside the sqrt a bit to: [(a-b)2 + c 2 ]/2 a2 -2ab + b2 + c2 = (a-b)2 + c2 λ1 = (a+b) + sqrt{(a-b)2 +c 2}/2 and λ2 = (a+b) - sqrt{(a-b)2 + c2}/2 now these expressions for Lambda are too difficult for me to use to solve for eigenvectors- sidinsky
- Post #5
- Forum: Calculus and Beyond Homework Help
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Please help with this matrix question Solve for Eigenvales, and Eigenvectors
is there any way this expression can be simplified further? I am sort of having trouble with the algebra :S- sidinsky
- Post #3
- Forum: Calculus and Beyond Homework Help
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Please help with this matrix question Solve for Eigenvales, and Eigenvectors
M = (a c) (c b) Sorry for the double sets of brackets, its all in one. I'll also show as far as i got below: [a-λ c] => (a-λ)(b-λ) - c^2 = λ^2 + (-a-b)λ + (ab-c^2) =0 [c b-λ] => then using the quadratic formula: λ = [-(-a-b) +/- Sqrt{(-a-b)^2 - 4(1)(ab-c^2)}]/ 2 then...- sidinsky
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- Eigenvectors Matrix
- Replies: 4
- Forum: Calculus and Beyond Homework Help