Recent content by silvashadow

Even if it's quadratic, why wouldn't you be able to solve for t?

Why can't you solve for t?

Yes, when the object is in freefall on Earth, gravity = a = 9.8m/s^2 down. Signs are optional but you could say -9.8n/s^s. In 2D, the gravity is always 9.8m/s^2 down on the object. It doesn't matter how the object is moving or thrown, gravity is always down.

Hitchhikers reference eh? The other object should be the falling whale.

I just gave you the answer.

Oh I see. Thanks for setting me straight. I'm still learning and your opinion is very helpful to me.

Area of wire, cross section area.

Well, circumference=pi*diameter, lol 102 turns = 102 circumferences

Oh I see. What's the step after finding R?

The graph of the acceleration is the graph of the derivative of the v-graph. Find the slope at each second and graph it onto a new graph. The a-graph is not linear.

Isn't the L for B=UIN/L the length of the solenoid not the length of the wire?

Break the velocity into components.

Yes, i know.

Wait, I think it was the d for the 4th second, from 3-4s. Because the first second is 0-1s, second second is for 1-2s, etc. So Vf=vo+at V@3=5+9.8*3 and V@4=5+9.8*4 Vf^2=Vo^2+2ad (V@4)^2=(V@3)^2+2*9.8*d Find d

Well, d=Vot+.5at^2 so d should be 98.4m. Did you get that?