How can you design a digital to analogue converter such that it has a squared output. i.e. the analog equivalent of the digital step is smaller at the lower voltage levels than at the higher voltage levels
May anyone please help with the method of getting Thevenin Equivalent resistance (RTH) for the attached circuit. I have already found VTH to be 8V.
Sim
(e) The speed of the traveling wave is given by v = λf = (2.78 m)(7.96Hz) = 22.13 m/s
is this correct? it seems to me the wavelength λ = 2pi/k or 2pi/3.4m = 1.85m thus v=1.85m * 7.96Hz = 14.70m/s
comments?
Thanks! you are right, didn't notice the mistake.
I recognise the exam is tommorow so here is what I got from another source.
Solution:
Visualize: What does the third harmonic mode look like ?
y(x,t) = (5.60cm) sin [(0.0340 rad/cm)x] sin [(50.0 rad/s)t]
Compare with standing wave expression
y = 2A sin kx sin ωt
λ3
L
(a) Recall that...